Web22 okt. 2024 · 已知如下一组规则:r1:ifE3andE4orE5thenE1 (0.8)r2:if E1 then H (0.6) r3:if E2 then H (0.7) r4:if E6 then H (0.8)已知CF(E3)=0.9,CF(E4)=0.8,CF(E5)=0.6,CF(E2)=0.6CF(E6)=0.4。 用 … Web文档网 免费word文档在线阅读与下载中心
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WebThis tutorial demonstrates how to use the IF Function in Excel and Google Sheets to create If Then Statements. IF Function Overview The IF Function Checks whether a condition is met. If TRUE do one thing, if FALSE do another. How to Use the IF Function Here’s a … Click OK, and then OK once again to return to the Conditional Formatting Rules … This tutorial will demonstrate how to calculate the “subtotal if”, performing the … VBA Coding Examples for Excel! Searchable list of ready-to-use VBA … The functionality of the LOOKUP Function is then the same as it was in our first … =COUNT(FIND({0,1,2,3,4,5,6,7,8,9},B3))>0. The formula above checks for the digits … Review our list our growing list of 100+ Excel formula examples. Examples … Excel. Formulas Tutorial. Learn 30 of Excel’s most-used functions with 60+ … Learn VBA Online - A Tutorial For Beginners: Learn VBA Online with this … Web15 jul. 2024 · 不确定性推理:可信度计算 1、设有如下一组推理规则: r1: IF E1 THEN E2 (0.6) r2: IF E2 AND E3 THEN E4 (0.7) r3: IF E4 THEN H (0.8) r4: IF E5 THEN H (0.9) 且已知CF (E1)=0.5, CF (E3)=0.6, CF (E5)=0.7。 求CF (H)=? 解: (1) 先由r1求CF (E2) CF …
Web设决策表如表所示,求该决策表的分明矩阵。其中a,b,c,d为条件属性,e为决策属性。 点击查看答案 http://www.doczj.com/doc/768367183.html
Web17 jan. 2024 · 设有三个独立的结论h1,h2,h3及两个独立的证据e1,e2,它们的先验概率和条件概率分别为 p(h1)=0.4, p(h2)=0.3, p(h3)=0.3, p(e1 h1)=0.5, p(e1 h2)=0.3, p(e1 h3)=0.5, p(e2 h1)=0.7, p(e2 h2)=0.9, p(e2 h3)=0.1, 试用概率方法分别求出: … Web1 mrt. 2010 · 人工智能课后习题第6章 参考答案
Web17 okt. 2016 · 6.11设有如下推理规则 r1: IF E1 THEN (100, 0.1) H1 r2: IF E2 THEN (50, 0.5) H2 r3: IF E3 THEN (5, 0.05) H3 且已知P (H1)=0.02, P (H2)=0.2, P (H3)=0.4,请计算当证据E1,E2,E3存在或不存在时P (Hi Ei)或P (Hi ﹁Ei)的值各是多少 (i=1, 2, 3)?.
WebGiven rules: IF E, AND E2 AND E3 THEN H (CF) IF E, OR ES THEN H (CF) where: CF (E1,e) = 1 CF1 (E2,e) = 0.5 CF1 (E3,e) = 0.3 CF2 (E,e) = 0.7 CF2 (Es,e) = 0.2 CF, (H,E) = 0.5 CF2 (H,E) = 0.9 a) Draw a tree illustrating how these rules support H b) Calculate the … pet covers for furniture nzWebcf2(h)=cf(h, e2) ×max{0, cf(e2)} (2) 用如下公式求e1与e2对h的综合可信度 . 例子 设有如下一组知识: r1:if e1 then h (0.9) r2:if e2 then h (0.6) r3:if e3 then h (-0.5) r4:if e4 and ( e5 or e6) then e1 (0.8) 已知:cf(e2)=0.8,cf(e3)=0.6,cf(e4)=0.5,cf(e5)=0.6, … pet covers for furniture wayfairWeb人工智能教程习题及答案第4章习题参考解答. 4.1什么是不确定性推理?. 有哪几类不确定性推理方法?. 不确定性推理中需要解决的基本问题有哪些?. 4.2什么是可信度?. 由可信度因子CF (H,E)的定义说明它的含义。. 4.3什么是信任增长度?. 什么是不信任增长度?. pet covers for couches waterproofWeb19 sep. 2024 · Sorted by: 7. The answer to your confusion is that in order for three events A, B and C to be mutually independent it is necessary but not sufficient that P ( A ∩ B ∩ C) = P ( A) × P ( B) × P ( C) (condition 1). The other condition that must be met is that each pair of events must also be independent [so A and B must be independent, B and ... pet covers for long sofasWebGiven rules: IF E, AND E2 AND E3 THEN H (CF) IF E, OR ES THEN H (CF) where: CF (E1,e) = 1 CF1 (E2,e) = 0.5 CF1 (E3,e) = 0.3 CF2 (E,e) = 0.7 CF2 (Es,e) = 0.2 CF, (H,E) = 0.5 CF2 (H,E) = 0.9 a) Draw a tree illustrating how these rules support H b) Calculate the certainty factors CF: (H,e) and CF2 (H,e) Question: 2. pet covers for leather sofaWebP (H1 E1)= (LS1×P (H1)) / ( (LS1-1)×P (H1)+1) = (100×0.02) / ( (100 -1)×0.02 +1) =0.671. P (H2 E2)= (LS2×P (H2)) / ( (LS2-1)×P (H2)+1) 可见,H2原来的概率是0.01,经过上述推理后得到的后验概率是0.06395,它相当于先验概率的6倍多。. 3设有如下推理规则. r1:IF … star citizen heavy armor setsWeb设有如下规则: R1: IF E1 THEN H (0.8) R2: IF E2 THEN H (0.6) R3: IF E3 THEN H (-0.5) R4: IF E4 AND (E5 OR E6) THEN E1 (0.7) R5 :IF E7 AND E8 THEN E3 (0.9) 且已知. CF(E2) = 0.8, CF(E4) = 0.5, CF(E5) = 0.6, CF(E6) = 0.7, CF(E7) = 0.6, CF(E8) = 0.9. 求: H 的综合 … star citizen heavy armor